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C语言 编写一个程序,包括两个函数,在主函数中输...

#include<stdio.h> double avg(double *marks) { double sum = 0.0; int i; for(i = 0; i < 5; i++) sum += marks[i]; return sum / 5.0; } int main(void) { double marks[8]; int i; for(i = 0; i < 5; i++) scanf("%lf", &marks[i]); printf("%.2lf\n", avg(marks)); return 0; }

#include using namespace std; int max(int,int); int max(int m,int n){return(m>n)?m:n;} int main(){ cout>x>>y>>z; coutcout

#include "stdio.h" int fun(int a[],int count,int *psum,float *paverge); void main() { int a[5]; int count; int sum; float averge; int i; for(i=0;i<5;++i) scanf("%d",a+i); count=fun(a,5,&sum,&averge); printf("\n%d %d %.2f",count,sum,averge); } int fun(int

#include <stdio.h> int main(){ int sum(int, int); int operand1, operand2; printf("Please key in two integers:\n"); scanf("%d,%d", &operand1,&operand2); printf("The sum of the two integers is %d\n",sum(operand1,operand2)); return 0; } int sum(int a, int b){ return a + b; }

#include <stdio.h>#include <stdlib.h>int cmp(const void*a,const void *b){ return *(int *)a-*(int *)b;//得到的结果为从小到大.}int main(){ int i,a[10]; printf("请依次输入10个整数:\n"); for(i=0;i<10;i++) scanf("%d",&a[i]); qsort(a,10,sizeof(a[0]),cmp);//此函数为快速排序 printf("排序结果为:\n"); for(i=0;i<10;i++) printf("%d ",a[i]); return 0;}

代码供参考: #include<stdio.h> void main() { void range(char b[],int n); char a[10]; int i=10; gets(a); range(a,i); puts(a); putchar('\n'); } void range(char b[],int n) { int i,j,t; for(j=n-1;j>0;j--) for(i=0;i<j;i++) if(b[i]>b[i+1]) { t=b[i]; b[i]=b[i+1]; b[i+1]=t; } }

关于# include <alloc.h>问题你看看这个 我将你代码改了点就没的错误了,代码如下:# include <stdio.h>#include <malloc.h> struct Worker { int num; float pay; struct Worker *next; }; int n; int main() { struct Worker *head,*create(void); void list(struct

#include<stdio.h> float mul(float a,float b) { return a*b; } int main() { float a,b; printf("请输5261入41021653a和内b:容"); scanf("%f %f",&a,&b); printf("积:%f\n",mul(a,b)); return 0; }

#include<stdio.h> void stringcat(char string1[],char string2[],char string[]) { int i,j; for(i=0;string1[i]!='\0';i++) string[i]=string1[i]; for(j=0;string2[j]!='\0';j++) string[i+j]=string2[j]; string[i+j]='\0'; } void main() { char *s1="abcdefg",*s2="hijklmn",s[80];

编写个函数求两个整数的和与差,在主函数中调用该函数求两个整数的相与差. 请帮忙给出正确答案和分析,谢谢! 令K1和K2断开,K3和K4分别开通和关断进行电桥检测.K3开通,K4断开,测得电阻

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