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C语言的:输入1个实数x,计算并输出下式的值,直到...

#include float nypow(float x,int n) { int sign=1; if(n sign=-1; n=n*sign; } if(n==0)return 1; float t=x; while(n>1) { n--; t*=x; } if(sign==-1) t=1.0f/t; return t; } int fact(int n) { if(n==0)return 1; int t= n; while(n>1) { n--; t*=n; } return t; } int main() { float x,t=1.0f,zero

//程序采用C++编写 如果需要的话 请自行改编成C 改编也很简单#include "stdafx.h" //可能需要去掉这一行#include <iostream>#include <cmath>#include <cstdlib> using namespace std; long fact(int a) //求阶乘 { int i=0; long sum=1; if (a==1)

我怀疑这道题的样例有问题,也可能是我的编译器上设定的精度不够高.#include <stdio.h> long long fact(int n) { int i; long long res=1; for(i=2;i<=n;i++) res *= i; return res; } double mypow(double x,int a) { int i; double res=1.0; for(i=0;i<a;i++) res *= x

#include#include double ab(double n){ int i; double s=1; for(i=1;is=s*i; return s;} void main(){ double c,d=0,x,j=1; scanf("%lf",&x); while(fabs(pow(-1,j-1)*pow(x,j)/ab(j))>pow(10,-5)) { c=pow(-1,j-1)*pow(x,j)/ab(j); d=d+c; j++; } printf("%lf",d); }

“getch”: 找不到标识符.

C代码:#include<stdio.h>#include<math.h>//fabs() int main() { double x,s,a;//为了提高精度,我把它们定义成双精度的.int i; scanf("%lf",&x);//注意x为弧度,输入的值过大没意义只要在-2*∏~2*∏即可.因为C语言的运算精确度有限.例如输

#include#include int main() { double esp; double s=0.00; double tmp = 1.0; int i=1, m=1; printf("Inputeps:"); scanf("%lf", &esp); while(fabs(tmp)>esp) { tmp = 1.00/i; s += (m*tmp); i +=4; m *= -1; } printf("S = %lf\n", s); return 0; }

#include int main() { int x,y; printf("please input a number:\n"); scanf("%d\n",&x); if(x{ y=x; printf("y=%d\n",y); } else if(x>1&&x { y=2*x-1; printf("y=%d\n",y); } else { y=3*x-11; printf("y=%d\n",y); } return 0; }

#include double fun(double x) { double y; if(x y = x; else if(x> 1 && x y = 2.0 * x - 1; else y = 3.0 * x - 11; return y; }// for test int main() { double x, y; printf("input x:"); scanf("%lf", &x); y = fun(x); printf("y=f(x)=%lf", y); return 0; }

#include //希望对您有用#include int main() { int x, y; printf( "please enter the number: " ); scanf( "%d", &x ); if( x y = x; else if( x y = 2 * x - 1; else y = 3 * x - 11; printf( "y = %d\n", y ); system( "pause" ); return 0; }

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