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C语言函数调用加减乘除

改成:/* HELLO.C -- Hello, world */#include "stdio.h"#include "conio.h" main() { int chu(int a,int b); int cheng(int a,int b); int jian(int a,int b); int jia(int a,int b); int chh(char c, int a, int b); int a,b,result; char ch,c; printf("please input a,b: "); scanf(

加减乘除依次如下(除法没有判断除数为0的异常情况):int Add(int a, int b) { return a + b;}int Subtract(int a, int b) { return a - b;}int Multiply(int a, int b) { return a * b;}int Devide(int a, int b){ return a/b; }

改成“for(;y=='y';)”就可以了的!for语句的三个参数,第一个是进行初始化的,第二个是用来判断的,第三个是在语句最后进行运算的.不懂可以追问,望采纳!

#include <stdio.h> int main() { double n,m; printf("请输入两个数:"); while(scanf("%lf%lf",&n,&m)!=EOF) { printf("%.lf + %.lf=%.lf\n",n,m,n+m); printf("%.lf - %.lf=%.lf\n",n,m,n-m); printf("%.lf * %.lf=%.lf\n",n,m,n*m); printf("%.lf / %.lf=%.2lf\n",n,m,n/m); printf("请输入两个数:"); } }

#include#includedouble jia(double a,double b){ return a+b;}double jian(double a,double b){ return a-b;}double cheng(double a,double b){ return a*b;}double chu(double a,double b){ return a/b;}double juedui(double a){ return a>0 ? a : -a;}double

#include <stdio.h>#include <math.h> void main() { float a,b; char c; printf("\n input a:"); scanf("%f",&a); printf("\n input b:"); scanf("%f",&b); printf("\n input c:"); scanf("%c",&c); printf("\n%c",c); switch(c) { case '+': printf("a+b=%f",

#include<stdio.h>#include<stdlib.h> int _add(int a,int b) { return a+b; } int _minus(int a,int b) { return a-b; } int _muti(int a,int b) { return a*b; } double divide(int a,int b) { if(!b) { printf("Error!\n"); exit(1); } return (double)a/b; } int main() { int a,b; char c;

#include "stdio.h" main() {int a,f,sum; float b; // 这里浮点类型 a=32; // 这里分号 b=1.8; scanf("%d",&f); // 这里 scanf用法 sum=(f-a)/b; // 这里括号,运算顺序 printf("sum is %d\n",sum); getch(); } 都是小错误. 混合运算加好括号就可以了,跟普通数学公式的意思一样.

#include<stdio.h>void add(float a,float b){ printf("%f",a+b);}void sub(float a,float b){ printf("%f",a-b);}void mul(float a,float b){ printf("%f",a*b);}void div(float a,float b){ printf("%f",a/b);}int main(){ int c; float a,b; printf("两数相加,选1;\n");

#include<stdio.h> double jia(double a,double b){ return a+b;} double jian(double a,double b){ return a-b;} double cheng(double a,double b){ return a*b;} double chu(double a,double b){ return a/b;} int modd(int a,int b){ return a%b;} int main(){ double a,

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